Question 1:
First let's compare the side lengths.
Let's make a fraction dividing the larger side and the smaller side.
[tex] \dfrac{10}{4} = \dfrac{5}{2}[/tex]
The larger side is 5/2 times larger than the smaller side.
Note that if two polygons are similar and the side length of one polygon is x times larger than the corresponding side of another polygon, than the area of the larger polygon is x² times larger than the smaller one.
This means that the area of the larger pentagon must be (5/2)² times larger than the smaller one.
A=[tex](5/2)^2*30=(25/4)*30=\dfrac{375}{2}=187.5[/tex]
Your answer is the first choice.
Question 2:
Let's compare the dimensions of both rooms.
[tex]8 \rightarrow 24[/tex]
[tex]10 \rightarrow 30[/tex]
The larger room has dimensions 3 times larger.
This means that the area of the larger room must be 3² times larger, or 9 times larger.
Multiply the cost of the smaller room by 9.
[tex]350*9=3150[/tex]
Your answer is the second choice. Hope this helps! :)
