Answer:
a , b, c are only applicable in graph.
Step-by-step explanation:
Given : The function [tex]f(x)=3sin(\frac{x}{4}+1)-\frac{1}{2}[/tex]
To find : Which of the following are correctly represented in the graph?
Solution :
General form of sin function is [tex]y=A sin(B(x-C)+D[/tex]
Where A is the amplitude
[tex]B=\frac{2\pi}{\text{Period}}[/tex]
D is the vertical shift.
C is the horizontal shift or phase shift.
Comparing with the general form:
[tex]f(x)=3sin(\frac{x}{4}+1)-\frac{1}{2}[/tex]
Transform little bit we get,
[tex]f(x)=3sin(\frac{1}{4}(x-(-4)))-\frac{1}{2}[/tex]
a. Amplitude is [tex]A=3[/tex]
It is correct.
b. Vertical shift is [tex]D= -\frac{1}{2}[/tex]
it is correct.
c. Horizontal shift [tex]C=-4[/tex]
It is correct.
d. Period is [tex]P=\frac{2\pi}{B}[/tex]
[tex]P=\frac{2\pi}{\frac{1}{4}}[/tex]
[tex]P=8\pi[/tex]
It is not correct .
Actual period in graph is [tex]2\pi[/tex]
e. The horizontal expansion or compression
It also not correct because period is not correct.
The expansion and compression depends on the period.
Therefore, a , b, c are only applicable in the graph.
