Using the normal distribution, it is found that P(z < −2.1) = 0.0179.
The z-score of a measure X in a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
From the z-table, we have that Z = -2.1 has a p-value of 0.0179, hence P(z < −2.1) = 0.0179.
More can be learned about the normal distribution at https://brainly.com/question/24663213
