Jesse is incorrect, because the equation of the graph should be [tex]f(x) = \sin(\frac{x}{3})[/tex]
From the question, we understand that the period is 3 times sin x.
The above claim is wrong.
Given that, the period (B) is 3.
i.e B = 3
The function is represented as:
[tex]f(x) = \sin(\frac{2\pi}{B})[/tex]
So, we have:
[tex]f(x) = \sin(\frac{2\pi}{3})[/tex]
Represent [tex]2\pi[/tex] with x
[tex]f(x) = \sin(\frac{x}{3})[/tex]
Hence, the equation of the graph should be [tex]f(x) = \sin(\frac{x}{3})[/tex]
Read more about sine functions at:
https://brainly.com/question/9565966