Mr. Jimenez deposited money into an account in which interest is compounded quarterly at a rate of 2.6%.

How much did he deposit if the total amount in his account after 4 years was $7160.06, and he made no other deposits or withdrawals?

Formula Is : A = P ( 1 + r/n ) ^ n * t

Answer Choices:

a. $6455

b. $6798

c. $6887

d. $6977

Respuesta :

The answer is A.

A is the amount after t years, P is the  amount originally deposited, r is the interest rate, and n is how often the interest is compounded per t.

Plug in what we know and solve for P:

[tex]7160.06=P(1+ \frac{0.026}{4})^{(4)(4)} [/tex]

P = [tex] \frac{7160.06}{(1+ \frac{0.026}{4} )^{16}} = 6454.999 [/tex]

Answer:

Option a. [tex]\$6,455[/tex]  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have      

[tex]t=4\ years\\ A=\$7,160.06\\ r=0.026\\n=4[/tex]  

substitute in the formula above  and solve for P

[tex]7,160.06=P(1+\frac{0.026}{4})^{4*4}[/tex]  

[tex]7,160.06=P(1+\frac{0.026}{4})^{4*4}[/tex]  

[tex]P=7,160.06/1.109227=\$6,455[/tex]