Respuesta :

calculista
Let
x------------> the length of rectangle
y-----------> the width of rectangle
A----------> area of rectangle

we know that
A= 182 units²
A=x*y  ------------> x*y=182 --------> equation 1
and
the length of a rectangle is 5 more than 3 times its width
then
x=5+3*y-------------> equation 2
substitute 2 in 1
(5+3y)*y=182--------> 5y+3y²=182------------> 3y²+5y-182=0

using a graph tool------------> I solve the quadratic equation
see the attached figure
the solution is 
y=7
x*y=182-----------> x=182/7----------> x=26

the answer is
 the length of rectangle is 26 units
the width of rectangle is 7 units



Ver imagen calculista

The length and width of the given rectangle with area of 182 square units is; Length = 26 units and width = 7 units

Area of a Rectangle

Let the length of the rectangle be x

Let the width of rectangle be y

Let the area of rectangle be A

Formula for area of rectangle is;

A = length * width

Thus;

A = xy

We are told that area is 182 square units. Thus;

xy = 182 sq.units   -----(eq 1)

Also the length of the rectangle is 5 more than 3 times its width. Thus;

x = 3y + 5   ------(eq 2)

Put 3y + 5 for x in eq 1 to get;

y(5 + 3y) = 182

3y² + 5y = 182

3y² + 5y - 182 = 0

Using online quadratic equation calculator gives; y = 7

Thus;  x = 182/7

x = 26

Read more about area of a rectangle at; https://brainly.com/question/13048427

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