The first thing we need to do is get ZERO on the opposite side of the quadratic expression. We can do this by subtracting 8 from both sides. You will get this:
x^2 + 4x - 4 = 0
Now that we have a quadratic expression equaling ZERO, we need to use the quadratic formula: x= [tex] \frac{-b + or - \sqrt{b^2 - 4ac} }{2a} [/tex]
a= coefficient of x^2
b= coefficient of x
c= last term
[tex] \frac{-4 + or - \sqrt{16 +16} }{2} = \frac{-4 + or - 4 \sqrt{2} }{2} = -2 +or- 2 \sqrt{2} [/tex]
The final answer would be x = [tex]x = (-2+ \sqrt{2}) or (-2 - \sqrt{2} [/tex]
