Respuesta :
Since AK = KD, then the triangle ABD is isosceles,
Then BD = AB. Denote AB by x and AK by y.
Then,
2x+4y=24 (the perimeter)
cos 60=y/x.
From the second equation we get [tex]y=0.5x[/tex]
Plug in the first equation we get:
[tex]2x+4(0.5x)=24\\2x+2x=24\\4x=24\\x=6[/tex]
We deduce that [tex]BD=6.[/tex]
Then BD = AB. Denote AB by x and AK by y.
Then,
2x+4y=24 (the perimeter)
cos 60=y/x.
From the second equation we get [tex]y=0.5x[/tex]
Plug in the first equation we get:
[tex]2x+4(0.5x)=24\\2x+2x=24\\4x=24\\x=6[/tex]
We deduce that [tex]BD=6.[/tex]
Answer:
Since AK = KD, then the triangle ABD is isosceles,
Then BD = AB. Denote AB by x and AK by y.
Then,
2x+4y=24 (the perimeter)
cos 60=y/x.
From the second equation we get
Plug in the first equation we get:
We deduce that
Step-by-step explanation: