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How much heat is needed to change 5.42 grams of solid gold to liquid gold at its melting point of 1,063°C? The latent heat of fusion of gold is 66.6 J/g.

Respuesta :


[tex]5.42 \times 66.6 = 360.972[/tex]
360.972 J

Answer:

360.97 J

Explanation:

mass of gold, m = 5.42 g

Latent heat of fusion, L = 66.6 J/g

The amount of heat required to convert 1 kg of solid into liquid state at its melting point is called latent heat.

L = Heat / mass

So, L = Q / m

Q = m L

Where, Q is the amount of heat supplied and L be latent heat of fusion amd m be the mass of substance.

Q = 5.42 x 66.6

Q = 360.97 J

Thus, the amount of heat required to melt the desired amount of gold is 360.97 J.

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