Respuesta :

Janay1012
x in (-oo:+oo)

(1/3)*((6/5)*x-3) = 0

1/3*(6/5*x-3) = 0
( 1/3 )

1/3 = 0

x belongs to the empty set

( 6/5*x-3 )

6/5*x-3 = 0 // + 3

6/5*x = 3 // : 6/5

x = 3/6/5

x = 5/2

x = 5/2
david8644

Answer:

2/5x-1

Step-by-step explanation:

In order to solve this you just have to multiply the factors that are inside the parenthesis by 1/3:

[tex]\frac{1}{3}(\frac{6}{5}x-3)\\\frac{6}{3(5)}x -\frac{3(1)}{3} \\\frac{2}{5}x-1[/tex]

By reducing the fraction you get that the result would be 2/5x-1 when expanding the multiplication of  1/3(6/5x-3)

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