part one: How do you solve a system of equations approximately using graphs and tables?

part 2: A lake has a native population of 1,000 frogs. The native frog population increases at a rate of 200 frogs per year. A new species of 10 frogs migrates to the lake. This new species’ population increases at a rate of 50% per year. When will the two populations equal each other? Select to reveal each frog population’s growth model.

the rest: A system of equations can be created with the two functions to determine when the populations will have the same population output value, y.
y = 200x + 1,000
y = 10(1.5x)
To determine when the populations will be equal, set the equations equal to each other, and solve for x.
200x + 1,000 = 10(1.5x)
This equation is a little more challenging to solve by algebraic methods. In this lesson, you will solve systems of equations like the one above approximately by effectively using technology and tables.

This problem can be solve by graphing (technology), as suggested.
The answer is posted as an attached image. We see that after about 14.75 years, the invading species will surpass the indigenous population.

If it needs to be solved mathematically and accurately, the math is a little more advanced, using the bisection method, or Newton's method.
However, we can also do that by trial and error, starting from 14.75. It is easier than you might think.

Post if you would like to have more information on one or the other methods.

Note: the scale of y has been shrunk by 1000, so each unit on the y-axis represents 1000 frogs.