Respuesta :
1. Height of the object is 5 cm
The object distance (u) is 18 cm
The focal length is 10 cm
To calculate the image distance (v) we use;
1/f=1/v+1/u
1/v = 1/10-1/18
= 8/180
Therefore v = 180/8
= 22.5 cm
2. Height of the image
Magnification = v/u = Height of image/height of object
Therefore;
22.5/ 18= x/5
x = (22.5×5)/18
x = 6.25 cm
Therefore; the height of the image is 6.25 cm
The object distance (u) is 18 cm
The focal length is 10 cm
To calculate the image distance (v) we use;
1/f=1/v+1/u
1/v = 1/10-1/18
= 8/180
Therefore v = 180/8
= 22.5 cm
2. Height of the image
Magnification = v/u = Height of image/height of object
Therefore;
22.5/ 18= x/5
x = (22.5×5)/18
x = 6.25 cm
Therefore; the height of the image is 6.25 cm
Answer:
The first one is 22.5
the second one is -6.25
Explanation:
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