Let's consider the smallest even integer = x.
then second even integer = (x + 2).
and third even integer = (x + 4).
So three consecutive even integers would be x, (x + 2), and (x + 4).
The sum of these numbers is -6. Its equation would be as follows :-
x + (x + 2) + (x + 4) = -6
3x + 6 = -6
3x = -6 - 6
3x = -12
x = -4
So first number = x = -4
second number = (x + 2) = -2
third number = (x + 4) = 0
Hence, three consecutive even integers are -4, -2, and 0
