Respuesta :
The rocket reaches a maximum height of 25 feet.
We substitute the velocity given into the equation:
h(t) = -16t² + 40t + h₀
We also use 0 for h₀, as the rocket is launched from the ground:
h(t) = -16t² + 40t + 0
To find the maximum, we find the coordinates of the vertex. To do this, we first find the axis of symmetry:
-b/2a = -40/(2*-16) = -40/-32 = 1.25
This is the x-coordinate of the vertex, which represents the amount of time in seconds. We substitute this back into our function:
h(1.25) = -16(1.25²) + 40(1.25) = 25
We substitute the velocity given into the equation:
h(t) = -16t² + 40t + h₀
We also use 0 for h₀, as the rocket is launched from the ground:
h(t) = -16t² + 40t + 0
To find the maximum, we find the coordinates of the vertex. To do this, we first find the axis of symmetry:
-b/2a = -40/(2*-16) = -40/-32 = 1.25
This is the x-coordinate of the vertex, which represents the amount of time in seconds. We substitute this back into our function:
h(1.25) = -16(1.25²) + 40(1.25) = 25
Answer:
25 feet
Step-by-step explanation:
other guy is legit
