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Luck6o
a = delta v over delta t delta v is calculated with final velocity less initial velocity so delta v is 14 - 6 that is 8m/s and delta t is calculated with final time less initial time as initial always is 0 then is 1 - 0 that is 1 then a = 8m/s over 1 that is 8 then the acceleration is 8m/s^2 (remember that is squared.)
Louli
Answer:
acceleration = 8 m/s²

Explanation:
Acceleration is defined as the rate of change of velocity.
This means that:
acceleration = [tex] \frac{v2 - v1}{t2 - t1} [/tex]
We are given that:
V2 = 14 m/sec
V1 = 6 m/sec
We are also given that the duration is 1 sec, this means that:
t2 = 1 sec
t1 = 0 sec

Substitute with the givens in the above equation to get the acceleration as follows:
acceleration = [tex] \frac{14-6}{1-0} [/tex] = [tex] \frac{8}{1} [/tex] = 8 m/s²

Hope this helps :)


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