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A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never include units in the answer to a numerical question.)

Respuesta :

skyluke89
For Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
[tex]F=ma[/tex]
Rewriting the acceleration as the increment of velocity [tex]\Delta v[/tex] in a time [tex]\Delta t[/tex]: [tex]a= \frac{\Delta v}{\Delta t} [/tex], F becomes
[tex]F=m \frac{\Delta v}{\Delta t} [/tex]
But given the definition of momentum: [tex]p=mv[/tex], then [tex]m \Delta v[/tex] represents the momentum change. So we can rewrite F as
[tex]F= \frac{\Delta p}{\Delta t} [/tex]
And re-arranging the formula we can calculate the value of the change in momentum:
[tex]\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s[/tex]
nuhulawal20

Given the force acting on the object, the change in its momentum is 4kg.m/s.

  • Force; [tex]F = 8.0N = 8 kg.m/s^2[/tex]
  • Mass; [tex]m = 0.7kg[/tex]
  • Time, [tex]t = 0.50s[/tex]

To determine the object's change in momentum, we use the Impulse Momentum Theorem:

The impulse applied to a body or matter is equal to the change in its momentum

Impulse = Change in Momentum

[tex]Impulse = F * dt[/tex]

Where F is the force applied and [tex]dt[/tex] is the elapsed time

Hence

[tex]Change \ in \ Momentum = F * dt[/tex]

We substitute our given values into the equation

[tex]Change \ in \ Momentum = 8 kg.m/s^2 * 0.50s\\\\Change \ in \ Momentum =4kg.m/s[/tex]

Therefore, given the force acting on the object, the change in its momentum is 4kg.m/s.

Learn more; https://brainly.com/question/14471691

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