Respuesta :
the amount of bromine present in the flask = 0.230 moles
Avagadro's number states the number of units present in a single mole.
Avagadro's number is 6.022 x 10²³ units, these could be atoms in the case of elements or molecules in compounds.
the number of bromine molecules in 1 mol = 6.022 x 10²³ molecules of Br bromine molecules in 0.230 mol = 6.022 x 10²³ molecules/mol x 230 mol
number of bromine molecules in the flask = 1.385 x 10²⁶ Br₂ molecules
Avagadro's number states the number of units present in a single mole.
Avagadro's number is 6.022 x 10²³ units, these could be atoms in the case of elements or molecules in compounds.
the number of bromine molecules in 1 mol = 6.022 x 10²³ molecules of Br bromine molecules in 0.230 mol = 6.022 x 10²³ molecules/mol x 230 mol
number of bromine molecules in the flask = 1.385 x 10²⁶ Br₂ molecules
Answer:
There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.
Explanation:
Moles of liquid bromine in the flask = 0.230 mol
As we know that 1 mole is equal to the Avogadro number.
[tex]1 mol=6.022\times 10^{23}[/tex] atoms/ molecules
So, number of bromine molecules in 0.230 moles of liquid bromine is:
[tex]=0.230\times 6.022\times 10^{23}=1.38506\times 10^{23} molecules[/tex]
There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.
