If we use 100 mL of
solution:
V(ethylene glycol - C₂H₆O₂) = 0,52 · 100 mL = 52 mL.
V(water) = 0,48 · 100 mL = 48 mL.
m(C₂H₆O₂) = 52 mL · 1,115 g/mL = 57,98 g.
n(C₂H₆O₂) = 57,98 g ÷ 62,07 g/mol = 0,934 mol.
m(H₂O)
= 48 mL · 0,988 g/mL = 47,424 g.
n(H₂O)
= 45,45 g ÷ 18 g/mol = 2,635 mol.
mole fraction of solvent: 2,635 mol / (2,635 mol
+ 0,934 mol) =0,73.
Raoult's Law: p(solution) = mole fraction of
solvent · p(solvent).
p(solution) = 0,73 · 92 torr = 67,33 torr.
