Two children with masses of 22 kg and 40 kg are sitting on a balanced seesaw. if the heavier child is sitting 0.7 m from the center, at what distance from the center is the lighter child sitting? answer in units of m.
first you should find their gravity [tex]40 \times 9.8 = 392 n\\ 22 \times 9.8 = 196n[/tex] now find the distance of the lighter child from the center [tex]196 x = 392 \times 0.7 \\ 196x = 274.4 \\ x = \frac{274.4}{196} = 1.4[/tex] the answer is 1.4m hope this helps
