Newton's second law for rotational motion we can find the answer for the force exerted by the bicep is:
F = 219.9 N
Parameters given
To find
Newton's second law for rotational motion establishes the relationship between torque, moment of inertia and angular acceleration, in the special case that angular acceleration is zero, it is called rotational equilibrium condition.
Σ τ = 0
τ = F r sin θ
Where τ is torque, F the force and (r sin θ) the distance perpendicular to the turning point.
The reference system is a coordinate system with respect to which measurements are made, in the attached we can see a diagram of the forces where the reference system is taken at the elbow and the counterclockwise turns are positive.
Let's write Newton's second law.
Suppose the forearm is homogeneous, so its center of mass is in the middle of the length.
[tex]- F x + W_{bicep} \frac{L}{2} + W_{ball} L = 0\\F = \frac{(\frac{m}{2} +M) g L }{x}[/tex]
Let's calculate.
F = [tex]\frac{(\frac{1.40}{2} + 1.0 ) 9.8 \ 0.33 }{0.025 }[/tex]
F = 219.9 N
In conclusion using Newton's second law for rotational motion we can find the answer for the force exerted by the bicep is:
F = 219.9 N
Learn more here: brainly.com/question/6855614
