Respuesta :
Answer:
The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.
Explanation:
Mass of titanium = 1.000 g
Moles of titanium =[tex]\frac{1 g}{47.87 g/mol}=0.0208 mole[/tex]
Heat capacity of the calorimeter ,c= 9.84 kJ/K
Initial temperature of the calorimeter ,T=25°C =298 K
Final temperature of the calorimeter ,T'= 60°C = 333 K
Heat gained by calorimeter = q
[tex]q=c\times \Delta T= 9.84 kJ/K\times(333K-298 K)=344.4 kJ[/tex]
Heat of combustion released when 1 g of titanium = -344.4 kJ
Heat if released that is why negative sign is used.
In 1 g of titanium = 0.0208 mole
Heat of combustion of 0.0208 moles of titanium = -344.4 kJ
Heat of combustion of 1 moles of titanium:
[tex]\frac{-344.4 kJ}{0.0208}=-16,557.69 kJ[/tex]
The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.