The value of Ari's rolls of coins is $113.00. If pennies and dimes come in rolls of 50 coins each, and nickels and quarters come in rolls of 40 coins each, which of these combinations could Ari have?

A. 5 rolls of pennies, 8 rolls of nickels, 4 rolls of dimes, and 7 rolls of quarters
B. 4 rolls of pennies, 8 rolls of nickels, 7 rolls of dimes, and 5 rolls of quarters
C. 4 rolls of pennies, 8 rolls of nickels, 5 rolls of dimes, and 7 rolls of quarters
D. 5 rolls of pennies, 8 rolls of nickels, 7 rolls of dimes, and 4 rolls of quarters

An odd number of rolls of pennies ($0.50 each) cannot be part of the solution, making answers A and D not worthy of consideration.

The correct choice is C.

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chisnau chisnau · Answer 2 · 2019-05-28T18:44:14+02:00

Answer:

Option C is correct.

Step-by-step explanation:

Given is :

The value of Ari's rolls of coins is = $113

The coins are pennies, dimes, nickels and quarters.

Total money is represented by = penny + nickle + dime + quarter All values in dollars are represented by:

113 = .01* pennies + .05* nickles + 0.1* dimes + 0.25* quarters

Further calculating we get,

113 = .01* 50*penny rolls + .05 * 40*nickle rolls + .1 * 50*dime rolls + .25 * 40*quarter rolls

[tex]113=.5p+2n+5d+10q[/tex]

where p is the number of penny rolls, n is the number of nickle rolls, d is the number of dime rolls, and q is the number of quarter rolls

Now checking all the options by putting values.

A. [tex]113=.5(5)+2(8)+5(4)+10(7)[/tex]

[tex]113\neq 108.5[/tex]

B. [tex]113=.5(4)+2(8)+5(7)+10(5)[/tex]

[tex]113\neq 103[/tex]

C. [tex]113=.5(4)+2(8)+5(5)+10(7)[/tex]

[tex]113=113[/tex]

D. [tex]113=.5(5)+2(8)+5(7)+10(4)[/tex]

[tex]113\neq 93.5[/tex]

Therefore, option C is the right option.