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To function properly a rainwater outflow pipe must drop exactly 1 inch for every 25 inches of horizontal distance . A design calls for a drainage pipe to drop 25 inches as it crosses a building 45 feet wide.will the drainage pipe function properly?

Respuesta :

acesharkbite
40 ft x 12 to convert it to inches.
480 inches / 25 inches = 19.2 Inches dropped.

Answer:

We know that the rainwater outflow pipe must drop 1 inch per 25 horizontal inches, this ratio would be:

[tex]\frac{y}{x}=\frac{1}{25}=0.04[/tex]

So, if the drainage pipe has this ratio, then it will function properly. Let's find out:

[tex]\frac{y}{x}=\frac{25}{540}[/tex]

Because, 45 feet is equivalent to 540 inches.

So, the ratio would be:

[tex]\frac{25}{540} \approx 0.046[/tex]

Therefore, the drainage pipe function will function properly because it has the same approximately ratio.

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