Answer:
The slope intercept form of the required line is [tex]y=\frac{-3}{2}x[/tex].
Step-by-step explanation:
If a line is defined as
[tex]Ax+By+C=0[/tex] ... (1)
Then the slope of the line is
[tex]m=\frac{-A}{B}[/tex]
The given equation is
[tex]3x+2y-6=0[/tex] .... (2)
From (1) and (2), we get
[tex]A=3, B=2, C=-6[/tex]
The slope of the line is
[tex]m=\frac{-3}{2}[/tex]
The slope of parallel line is same. So, the slope of required line is -3/2.
The slope intercept form of a line is
[tex]y=mx+b[/tex]
Where, m is slope and b is y-intercept.
The slope of required line is -3/2 and y-intercept is at (0,0).
[tex]y=\frac{-3}{2}x+0[/tex]
[tex]y=\frac{-3}{2}x[/tex]
Therefore the slope intercept form of the required line is [tex]y=\frac{-3}{2}x[/tex].
