Respuesta :
The ratio of height above the transit to the distance to the transit is the tangent of the angle.
.. height = 8 ft +(120 ft)*tan(36°) = 95 ft . . . . . . matches selection B
.. height = 8 ft +(120 ft)*tan(36°) = 95 ft . . . . . . matches selection B
Answer:
95 feet
Step-by-step explanation:
Refer the attached figure.
A surveyor moves 120 feet away from the base of the pole i.e. BC = 120 feet.
BC= ED = 120 feet (refer the figure)
Height of transit i.e. DC = 8 feet
DC = EB = 8 feet (refer the figure)
The angle of elevation to the top of the pole to be 36° i.e. ∠ADE = 36°
Height of pole = AE+EB
To find AE use trigonometric ratio
[tex]tan\theta = \frac{Perpendicular}{Base}[/tex]
[tex]tan36^{\circ}= \frac{AE}{ED}[/tex]
[tex]0.726= \frac{AE}{120}[/tex]
[tex]0.726*120= AE[/tex]
[tex]87.12 = AE[/tex]
Height of pole = AE+EB = 87.12+8 = 95.12 feet≈95 feet
Hence the height of pole is 95 feet
