Answer: 16.5 m/s
Explanation:
By law of conservation of energy:
[tex] \frac{kx^2}{2} = \frac{mv^2}{2} [/tex] --- (1)
Since k = Spring Constant = 850 N/m
x = 0.40 m
m = 500g = 0.5kg
v=?
Plug in the values in (1):
[tex] \frac{(850)(0.40^2)}{2} = \frac{0.5v^2}{2} \\ v = \sqrt{272} \\ v = 16.49 m/s\\ v = 16.5 m/s(approx)[/tex]
