Answer: 5/3 and - 1/3
Explanation:
1) Set the given function equal to 0: 9x^2 - 12x - 5 = 0
2) make 9x^2 = (3x)^2 and 12x = 4(3x)
=> (3x)^2 - 4(3x) - 5 = 0
3) Factor the polynomial:
(3x - )(3x + ) first stept of factoring.
Now find two numbers that sum - 4 and their product of - 5, those are -5 and + 1: =>
(3x - 5) (3x + 1) = 0
4) Set the two factors equal to 0:
3x - 5 = 0 => 3x = 5 => x = 5/3 ↔ one root
3x + 1 = 0 => 3x = - 1 => x = - 1/3 ↔ the other root.
