In △ABC, AB = 7 and AC = 17. Find m∠B to the nearest degree
68
38
21
87

Answer:
The m∠B is 68°
Step-by-step explanation:
Given the right angled triangle ABC in which right angled is at A.
AB = 7 units and AC = 17 units
we have to find the measure of ∠B.
By trigonometric ratios,
[tex]cot \angle B=\frac{AB}{AC}[/tex]
[tex]cot \angle=\frac{7}{17}[/tex]
[tex]\angle B=cot^{-1}(\frac{7}{17})[/tex]
[tex]\angle B=67.619864948\sim 68^{\circ}[/tex]
Hence, the m∠B is 68°
Option 1 is correct