Answer:
The height of the ball after t =1.5 second is 7.5 feet.
Description:
The basket ball shoots from a height of 6 feet, it increase the height 1.5 feet after 1.5 seconds.
Therefore, the basketball thrown at the rate of 1 feet/per second.
Step-by-step explanation:
Given: A player shoots a basketball from a height of 6 feet. The equation,
h(t) = [tex]-16t^2 + 25t + 6[/tex]
We need to find the height of the ball when t = 1.5 and describe the height.
plug in t = 1.5 in h(t) = [tex]-16t^2 + 25t + 6[/tex]
h(1.5) = [tex]-16(1.5)^2 + 25(1.5) + 6[/tex]
Simplifying the above expression, we get
h(1.5) = -36 + 37.5 + 6
h(1.5) = -36+43.5
h(1.5) = 7.5 feet
The height of the ball after t =1.5 second is 7.5 feet
Description:
The basket ball shoots from a height of 6 feet, it increase the height 1.5 feet after 1.5 seconds.
Therefore, the basketball thrown at the rate of 1 feet/per second.
