Respuesta :

carlosego
64r ^ 2-144r + 81
 For this case, what we can do is rewrite the second degree polynomial. 
 Apply resolvent:
 a = 64
 b = -144
 c = 81
 x = (- b +/- root (b ^ 2 - 4ac)) / 2a
 x = (- (- 144) +/- root ((- 144) ^ 2 - 4 * (64) * (81))) / 2 (64)
 x = (- (- 144) +/- root (0)) / 128
 x = 144/128
 x = 72/64
 x = 36/32
 x = 18/16
 x = 9/8
 Rewriting the polynomial:
 (8r-9) * (8r-9)
 Answer:
 The side length of the square is:
 (8r-9)

The dimension of the square is 1.125 by 1.125 units and the area of the square is 1.265625 square units.

What is a factorization?

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The given expression represents the area of a square is 64r² – 144r + 81.

The dimension of the square will be

Using the formula method, we have

64r² – 144r + 81

Then

[tex]\rm r = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Then we have

a = 64

b = –144

c = 81

Then

[tex]r = \dfrac{-(-144) \pm \sqrt{(-144)^2-4*64*81}}{2*64}\\\\\\r = \dfrac{144 \pm \sqrt{20736- 20736}}{128}\\\\\\r = \dfrac{144}{128}\\\\\\r = 1.125[/tex]

The dimension of the square is 1.125 by 1.125 units and the area of the square is 1.265625 square units.

More about the factorization link is given below.

https://brainly.com/question/6810544

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