Respuesta :
Shown below is the graph on the x-y plane.
Your equation has only one variable, so a graph on the number line is appropriate. It would extend outward from ±2, where the points would be indicated by open circles.
Your equation has only one variable, so a graph on the number line is appropriate. It would extend outward from ±2, where the points would be indicated by open circles.

Answer:
Given equation,
3|x| > 6 -----(1)
∵ [tex]\frac{1}{3}>0[/tex]
Thus, multiplying both sides of inequality (1) by [tex]\frac{1}{3}[/tex]
We get,
[tex]|x| > 2[/tex]
⇒ 2 < x or 2 < - x
⇒ 2 < x or -2 > x (when a > b where a > 0, b > 0, If c < 0 ⇒ ac < bc),
⇒ (2, ∞ ) ∪ (-∞, -2)
By plotting the above interval in the number line we can get the graph of the given equation ( shown below )
