Answer:
Area of wall = [tex] 94 \frac{47}{48} [/tex] ft
Explanation:
First, we know that:
1 in = 1/12 ft
Therefore, the dimensions of the wall would be as follows:
H = 7 ft 10 in = [tex] 7 \frac{10}{12} [/tex] ft
B1 = 10 ft 2 in = [tex]10 \frac{2}{12} [/tex] ft
B2 = 14 ft 1 in = [tex]14 \frac{1}{12} [/tex] ft
For the trapezium, area can be calculated using the following the following formula:
Area of trapezium = Average base * height = [tex] \frac{B1 + B2}{2} [/tex] * height
Substitute with the given to get the area as follows:
Area of wall = ([[tex]10 \frac{2}{12} [/tex] + [tex]14 \frac{1}{12} [/tex]] / 2) * [tex] 7 \frac{10}{12} [/tex]
Area of wall = [tex] 94 \frac{47}{48} [/tex] ft
Hope this helps :)
