SiriusBlack4577
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There are three questions. I'll give brainliest if you show your work for all three of them. Plz help and answer quickly!
What square root best approximates the point on the graph?
A square root of 5
A square root of 15
A square root of 28
A square root of 53

Hassan used the iterative process to locate the square root of 15 on the number line.
Which best describes Hassan’s estimation?
Hassan is correct because the square root of 15 is about 0.4
Hassan is correct because the point is on the middle of the number line.
Hassan is incorrect because the square root of 15 is less than 0.4
Hassan is incorrect because the point should be located between 0.1 and 0.2.

The point plotted on the number line is the square root of x.
What is the approximate value of x?
4
9
17
20

There are three questions Ill give brainliest if you show your work for all three of them Plz help and answer quickly What square root best approximates the poi class=
There are three questions Ill give brainliest if you show your work for all three of them Plz help and answer quickly What square root best approximates the poi class=
There are three questions Ill give brainliest if you show your work for all three of them Plz help and answer quickly What square root best approximates the poi class=

Respuesta :

battlefortroy
Hello! I apologize for any wait, I was away for some time. Once again, I apologize for any inconvenience, and if you have already moved on, I'll go ahead and explain this out anyways for future reference. 

1: What square root best approximates the point on the graph?
Well, here you are shown a number line. On the number line, there is a point. Guesstimating it shows it's around 5.1-5.2. It is definitely lower than 5.5, as that would be directly in the middle of 5 and 6. 

Well, the answer are:
A square root of 5
A square root of 15
A square root of 28
A square root of 53

Well, this question is a little unclear to me. I am considering if the question is stating that those numbers, 5, 15, 28, and 53 are ALREADY the sqaure root of a number, or if those 4 numbers are what you are supposed to find out which square root lines up to the point on the chart.

Because it seems that none of these four numbers would work with my first theory, I'll go with the simpler of the two, the latter. Meaning those four numbers are the numbers that you have to find the square root of, and the correct one should line up with the chart.

SO, pull out your calculator kiddo. You don't want to have to calculate square root by hand, you'll run out of paper/and or pencils before you know it. It usually takes a bit of time for each one, and considering you have multiple one's to calculate. . . Yeah, go with the calculator. 

So, plug in each of the numbers into a TI-84 or basically any calculator that works with square root calculations. 

Square root of 5: 2.2360679775
Square root of 15: 3.87298334621
Square root of 28: 5.29150262213
Square root of 53: 7.28010988928

Alright. Well, what do we know? From our guesstimation, the point looked to be close to 5.2

None of these match that EXCEPT C: 28

Your best shot for #1 is 28

2. Hassan used the iterative process to locate the square root of 15 on the number line. 

I'll be frank: I've never heard of the "iterative process" in my life, and if I have, i definitely can't recall. This is most likely a different term used for some other process that I probably DO know, but anyways, that's not quite relevant, so I'll carry on:

Looking at the graph we see H-man graphed his point on the number line at EXACTLY .45
We know this because the dot is directly in the middle of .4 and .5, and .45 is the best way to represent that (imagine .4 is .40, and .5 is .50 if this helps, the value is ultimately the same)

Now, H-man graphed this point specifically because he used his "process" to find the square root of 15. 

Once again, I'm not sure what this process is, but I'll help to the best of my ability. The square root of 15 is around 3.9

I'm assuming H-man's process simply moved around the decimal place, somehow. This I am not sure on, but it's the only thing that makes somewhat sense to me.

So, if this is correct, on his terms, the graphed point should be more like: 0.39

Now, his point is considerably further than this. This would mean (don't quote me on this) that Hassan is incorrect, and I would say this because the sqare root of 15 is less than .4

Yes, this doesn't make much sense to me, but if I'm correct, then this answer should also be correct. Relatively. 

3. The point plotted on the number line is the square root of x.
What is the approximate value of x?

Basically X represents the original number, and the numbers they give you are what they want you to choose the original number is. This is based on the point on the graph, which is at around 4.1, because this number is the square root of X.


To solve this, find the square roots of all 4 numbers (separately of course). 

The square root of 4 is: 2
The square root of 9 is: 3
The square root of 17 is: 4.12310562562
The square root of 20 is: 4.472135955

Now, from our guess we can clearly see the point is around 4.1
The answer that nearly matches this estimate EXACTLY is C: 17

Your choice here is 17

Total: 

#1=28
#2=Hassan is incorrect because the square root of 15 is less than 0.4 (guess)
#3=17

The square root which is best approximated by the point on the graph is given by: Option C: A square root of 28. Also, the square root of 15 lies between 3 and 4.

How to find the closest integer less than and greater than the square root of a number?

The function [tex]y = \sqrt{x}[/tex] is strictly increasing function for x ≥ 0.

Assuming that all the values of x are ≥ 1, whenever there is increment in the value of 'x', the value of y increases too.

That means, we've got:

[tex]x_1 < x_2 < x_3 \implies \sqrt{x_1} < \sqrt{x_2} < \sqrt{x_3} \: \text{(such that } x_1 \leq 1)[/tex]

Perfect square are those integers whose square root is an integer.

Let x-a be the closest perfect square less than x,

and let x+b be the closest perfect square more than x, then we get:
x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).

Then, we get:

[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]

Thus, [tex]\sqrt{x-a}[/tex] and  [tex]\sqrt{x+b}[/tex] are the closest integers, less than and more than the value of [tex]\sqrt{x}[/tex]. (assuming x is non-negative value).

Now, from the first graph, we see that the value of the square root is between 5 and 6, therefore, we have:

[tex]5 < \sqrt{x} < 6[/tex]

Now, squaring all the sides, we get:

[tex]25 < x < 36[/tex]

Thus, the number out of the given options, whose square root lies between 5 and 6 is given by: Option C: A square root of 28

It is because 25 < 28 < 36, and no other option satisfies this,

For square root of 15, the perfect squares closest to 15 are 9 and 16, therefore, we get:

[tex]\sqrt{9} < \sqrt{15} < \sqrt{16}\\\\3 < \sqrt{15} < 4[/tex]

Thus, the square root which is best approximated by the point on the graph is given by: Option C: A square root of 28. Also, the square root of 15 lies between 3 and 4.

Learn more about square root here:

https://brainly.com/question/7200235

#SPJ3

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