Respuesta :
Okay, I've been working on this problem for about two hours already and I just cant seem to make it work, I know I'm missing something with the equations but I cant seem to figure it out. I know that PV=NRT
and that in the problem I am given initial P, and T and R is the gas constant, leaving N and V as unknown. I also know that I can use V=RT/P to find the volume (I got .009886, and I don't think that is right) and then plug that back in to calculate N (I got 1.659795*10^-32, not sure about that) at the given temperature (35C=309.15K) but when I do all this I get an outrageous answer that cant possibly be right (P=5.703*10^-59? no way on earth). I don't know if I am maybe using the wrong formula, maybe the wrong constant, messing up on algebra somewhere or if my calculator is just fudging my answer (I do that sometimes). Someone please give me some pointers on how to set this problem up to get the right P at the end!
Thank you so much for the help guys, I think I actually understand what is going on with the algebraic organization (for once). When I do it myself I get an answer of 207,016 Pa which is 2.0431 atm, but the automated system I am using keeps telling me that is a wrong answer.
and that in the problem I am given initial P, and T and R is the gas constant, leaving N and V as unknown. I also know that I can use V=RT/P to find the volume (I got .009886, and I don't think that is right) and then plug that back in to calculate N (I got 1.659795*10^-32, not sure about that) at the given temperature (35C=309.15K) but when I do all this I get an outrageous answer that cant possibly be right (P=5.703*10^-59? no way on earth). I don't know if I am maybe using the wrong formula, maybe the wrong constant, messing up on algebra somewhere or if my calculator is just fudging my answer (I do that sometimes). Someone please give me some pointers on how to set this problem up to get the right P at the end!
Thank you so much for the help guys, I think I actually understand what is going on with the algebraic organization (for once). When I do it myself I get an answer of 207,016 Pa which is 2.0431 atm, but the automated system I am using keeps telling me that is a wrong answer.
