Respuesta :
pathagorean theorem:
[tex] {a}^{2} + {b}^{2} = {c }^{2} \\ {8}^{2} + {5}^{2} = {c}^{2} \\ 64 + 25 = {c}^{2} \\ 89 = {c}^{2} \\ \sqrt{89 } = \sqrt{ {c}^{2} } \\ the \: wire \: is \: 9.43ft[/tex]
[tex] {a}^{2} + {b}^{2} = {c }^{2} \\ {8}^{2} + {5}^{2} = {c}^{2} \\ 64 + 25 = {c}^{2} \\ 89 = {c}^{2} \\ \sqrt{89 } = \sqrt{ {c}^{2} } \\ the \: wire \: is \: 9.43ft[/tex]
The length of the stretched wire is required.
The length of the wire is 9.43 feet.
Pythagoras theorem
b = Length of the pole = 8 ft
a = Distance between bracket and base of pole = 5 ft
c = Length of wire
The two lengths form a right triangle.
From the Pythagoras theorem we have
[tex]c^2=a^2+b^2\\\Rightarrow c=\sqrt{a^2+b^2}\\\Rightarrow c=\sqrt{8^2+5^2}\\\Rightarrow c=9.43\ \text{feet}[/tex]
Learn more about Pythagoras theorem:
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