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When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 9.925 g. If the density of water is taken to be 0.9975 g/mL, what is the percent error for the 10 mL of water,

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ChemistryHelper2024
measured volume = 10 ml 
mass = 9.925 g 
density = 0.9975 g/ml
density = [tex] \frac{mass}{volume} [/tex] 
so actual volume = [tex] \frac{mass}{density} [/tex] = [tex] \frac{9.925}{0.9975} [/tex] = 9.95 mL
Percentage Error = [tex] \frac{measured volume - Actual volume}{actual volume} [/tex] x 100 
= [tex] \frac{10 - 9.95}{9.95} [/tex] x 100 = 0.5 % error

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