Respuesta :
Yes, that is correct. There are 1.25 moles in one liter of solution, and there are about 98 grams in one mole of H2SO4. Using this information we can readily eliminate A and B as answers, as there would be far more than 36 grams in 2.9 and 5.8 liters of this solution. 98 x 1.25 = 122.5 grams of H2SO4 in one liter, and we can then divide 36 into 122.5 to arrive at 0.29L.
Answer:
D. 0.29 L
Explanation:
To calculate the required volume, we can convert the concentration of the solution from M to g/L, keeping in mind the molar mass of H₂SO₄, 98 g/mol :
1.25 [tex]\frac{mol}{L}*\frac{98g}{1mol}=[/tex]122.5 g/L
So a concentration of 1.25 M of H₂SO₄ is the same as a concentration of 122.5 g/L.
Finally we divide 36 grams by the concentration:
[tex]\frac{36g}{122.5g/L}[/tex] = 0.29 L
So your answer was correct, it is option D.