Answer:
The new radius of the balloon is 17.8 cm.
Explanation:
Initial pressure of the air in the balloon =[tex]P_1[/tex] 1.0 atm
Radius of the balloon ,r= 17 cm
Volume of the spherical volume balloon = [tex]V_1=\frac{4}{3}\pi r^3[/tex]
Final pressure of the air in balloon =[tex]P_2[/tex]=0.87 atm
Radius of the balloon be R
Volume of the balloon be = [tex]V_2=\frac{4}{3}\pi R^3[/tex]
New radius of the balloon= R
According Boyle's Law:
[tex]P_1V_1=P_2V_2[/tex]
[tex]1.0 atm\times \frac{4}{3}\pi r^3=0.87 atm\times \frac{4}{3}\pi R^3[/tex]
R =17.80 cm
The new radius of the balloon is 17.8 cm.
