Hello!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.
To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
[tex]P_n*V_n=n*R*T_n \\ \\ n*R= \frac{P_n*V_n}{T_n} [/tex]
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
[tex] \frac{P_1*V_1}{T_1}= \frac{P_2*V_2}{T_2} \\ \\ P_2= \frac{P_1*V_1*T_2}{T_1*V_2}= \frac{1,10 atm*2,31 L *298 K}{287K*1,45 L}=1,82 atm [/tex]
Have a nice day!
