Respuesta :
Number of moles equals of potassium iodide;
The molar mass of potassium iodide is 166 g/mole
Moles = 300/166
= 1.8072moles
According to the equation;
2 moles of KI produces 1 mole of PbI2 9lead (ii) iodide
Therefore; the number of moles of lead (ii) iodide produced will be;
= 1.8072/2
= 0.9036moles
Thus the number of moles of lead (ii) iodide is 0.904 mole
Answer : The correct option is, (d) 0.904 mole
Explanation : Given,
Mass of potassium iodide = 300 g
Atomic mass of potassium iodide = 166 g /mole
First we have to calculate the moles of potassium iodide.
[tex]\text{Moles of KI}=\frac{\text{Mass of KI}}{\text{Molar mass of KI}}=\frac{300g}{166g/mole}=1.807mole[/tex]
Now we have to calculate the moles of lead(ii) iodide.
The given balanced chemical reaction is,
[tex]Pb(NO_3)_2+2KI\rightarrow PbI_2+2KNO_3[/tex]
From the given balanced chemical reaction, we conclude that
As, 2 moles of potassium iodide react to give 1 mole of lead(ii) iodide
So, 1.807 moles of potassium iodide react to give [tex]\frac{1.807}{2}=0.904[/tex] mole of lead(ii) iodide
Therefore, the number of moles of lead(ii) iodide produced are, 0.904 mole
