Respuesta :
[H+] of Lemon juice = 5.0 × 10^-2 M = 0.05M
So pH of lemon juice = - log [H+] = - log (0.05)
pH = - log (0.05)
pH = - (-1.3) = 1.3
So the pH of the Lemon Juice = 1.3
So pH of lemon juice = - log [H+] = - log (0.05)
pH = - log (0.05)
pH = - (-1.3) = 1.3
So the pH of the Lemon Juice = 1.3
Answer:
yes... the answer is B) 1.3
Explanation:
I made it on the unit test!