If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of NaCl would be made?
A. 467.52 g NaCl
B. 1014 g NaCl
C. 233.76 g NaCl
D. 649.05 g NaCl,
Number of moles of FeCl2 used = mass/ molar mass Number of moles = 507/126.751 = 4. If one mole of Fe reacts with two moles of sodium Then 4 moles of Fe produces 8 moles of sodium. Number of moles of sodium = mass/molar mass Molar mass of sodium chloride = 23 +35.5 = 58.5 g/mol Hence mass = 8 * 58.5 = 468 g. Hence Option A.
