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Consider the unbalanced equation for the combustion of hexane: αc6h14(g)+βo2(g)→γco2(g)+δh2o(g) part a balance the equation. give your answer as an ordered set of numbers α, β, γ, ... use the least possible integers for the coefficients. α, β, γ, δ = request answer part b determine how many moles of o2 are required to react completely with 6.4 moles c6h14. express your answer using two significant figures. n = mol

Respuesta :

Answer :

Part A : The value of [tex]\alpha, \beta, \gamma \text{ and }\delta[/tex] are 2, 19, 12 and 14 respectively.

Part B : [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].

Solution :

Part A :

The given unbalanced equation is,

[tex]\alpha C_6H_{14}(g)+\beta O_2(g)\rightarrow \gamma CO_2(g)+\delta H_2O(g)[/tex]

The balanced equation is,

[tex]2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)[/tex]

Part B :

From the balanced equation, we conclude that

2 moles of [tex]C_6H_{14}[/tex] react with 19 moles of [tex]O_2[/tex]

6.4 moles of [tex]C_6H_{14}[/tex] react with [tex]\frac{19moles}{2moles}\times 6.4moles=60.8moles=6.0\times 10^1moles[/tex] of [tex]O_2[/tex]

Therefore, [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].


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