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Pushing on the pump of a soap dispenser compresses a small spring. When the spring is compressed 0.54 cm, its potential energy is 0.0025 J.
(a) What is the force constant of the spring? (answer is in kN/M)
(b) What compression is required for the spring potential energy to equal 0.0078 J? (answer is in cm),

Respuesta :

Kalahira
We know, U of spring = (kx^2)/2 k = spring constant x = deflection from mean position a) Here, x = 0.54 cm = 0.0054 m U= 0.0025 J k = 2U/x^2 k = 0.0050/ (0.0054^2) k = 0.171 kN/m b) x = (2U/k) ^ 1/2 x = (0.0156/171) ^ 1/2 x = 0.0095 m x = 0.95 cm

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