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Help Please..?
A 20-kg barrel is rolled up a 20-m ramp to the back of a truck whose floor is 5.0 m above the ground. What work is done in loading one barrel into the truck?
A:980J
B:19,600J
C :4900J
D :imposible to tell because velocity is not given.,

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Kalahira
The answer is {A} 980 J. To obtain this answer you would use your Sin function on the calculator: Sin θ = 5 / 20 = 0.25 therefore θ = 14.4775° F net = m g sin θ = 20 * 9.8 * 0.25 = 49N W = F * d = 49 * 20 = 980 J ( my phone keyboard does not include the θ I had to copy the solution to “show the work” )

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