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Two very quick questions!!

1) If a pulley system with an actual mechanical advantage of 2 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?


If a pulley system with an actual mechanical advantage of 2,000,000 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?,

Respuesta :

Kalahira
The weight lifted by a machine to the applied force on a machine is called mechanical advantage. This is written as Mechanical advantage, M. A, = load(weight)/effort. So for 1) M.A = 2 and load = 2, 000lb = 8896.446N. So 2 = 8896.446/ effort Effort = 8896.446/2 = 4448.48 Similarly for M.A of 2, 000, 000 we have Effort = 8896.446/ 2, 000, 000 = 0.004448

Explanation:

1. Mechanical advantage of a pulley system, m = 2

Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.

[tex]m=\dfrac{F_L}{F_E}[/tex]

Here, [tex]F_L=2000\ lb[/tex]

[tex]F_E=\dfrac{F_L}{m}[/tex]

[tex]F_E=\dfrac{2000\ lb}{2}[/tex]

[tex]F_E=1000\ lb[/tex]

Hence, 1000 lb effort will be needed to move the car.

2. Mechanical advantage of a pulley system, m = 2,000,000

Value of load, [tex]F_L=2000\ lb[/tex]

Mechanical advantage, [tex]m=\dfrac{F_L}{F_E}[/tex]

[tex]F_E=\dfrac{F_L}{m}[/tex]

[tex]F_E=\dfrac{2000\ lb}{2000000}[/tex]

[tex]F_E=0.001\ lb[/tex]

Hence, 0.001 lb effort would be needed to move the car.

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