Respuesta :
Hey there! :D
We can subtract the equations from each other.
4x-3x=x
2y-2y=0
10-6=4
x=4 <== that's all we have left of the equation
Now plug that in to solve.
3(4)+2y=6
12+2y=6
2y=-6
y=-3
Solution: (4,-3)
I hope this helps!
~kaikers
We can subtract the equations from each other.
4x-3x=x
2y-2y=0
10-6=4
x=4 <== that's all we have left of the equation
Now plug that in to solve.
3(4)+2y=6
12+2y=6
2y=-6
y=-3
Solution: (4,-3)
I hope this helps!
~kaikers
Answer:
x = 4 and y = -3.
Step-by-step explanation:
Given : 4x + 2y = 10 and 3x + 2y = 6.
To find : Solve the system algebraically. Check your work.
Solution : We have given that
4x + 2y = 10 ----(1)
3x + 2y = 6.------(2)
Subtracting equation 2 from 1
4x + 2y = 10
(-)3x + (-)2y =(-) 6.
_____________
x + 0 = 4
x =4
Plug x = 4 in equation 1
4 (4) + 2y = 10.
16 + 2y = 10.
2y = 10 -16.
2y = -6.
On dividing by 2 both sides
y = -3.
Check:
Plug the values x =4 , y =-3 in equation 1
4 (4) + 2 ( -3) = 10
16 -6 = 10
10 =10
Verify,
Therefore, x = 4 and y = -3.