Respuesta :
1. Ans: Option (B) [tex]-6x^4[/tex]
Explanation:
Given: [tex]2x^4 - 8x^4[/tex]
Take the common out:
=> [tex]x^4(2 - 8)[/tex]
Hence: => [tex][tex]-6x^4[/tex][/tex] (Option B)
2. Ans: Option (D) [tex]-3y^5[/tex]
Explanation:
Given: [tex]6y^5 - 9y^5[/tex]
Take the common term(s) out:
=> [tex]y^5(6-9)[/tex]
Hence: => [tex]-3y^5[/tex] (Option D)
3. Ans: Option (B) [tex]9x^2 - 12x + 6[/tex] quadratic trinomial
Explanation:
Given: [tex]6 - 12x + 13x^2 - 4x^2[/tex]
The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.
=> [tex]13x^2 - 4x^2 - 12x + 6[/tex]
=> [tex]9x^2 - 12x + 6[/tex] (Option B)
4. Ans: Option (C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:
Common guppies: [tex]3.1x^2 +6.0x + 0.3[/tex]
Endler's guppies: [tex]4.2x^2 - 5.2x + 1.0 [/tex]
(add both)
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Total number: [tex]7.3x^2 +0.8x + 1.3[/tex]
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Hence the ans is Option(C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
5. Ans: Option (D) [tex]2x^2(133 - 18 \pi )[/tex]
Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = [tex]266x^2[/tex]
Now the area of the circular fountain:
Area of the Circular Fountain = [tex] \pi r^2[/tex]
Since, r=6x
Therefore,
Area of the Circular Fountain = [tex] \pi (6x)^2 = 36 \pi x^2[/tex]
Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = [tex]266x^2[/tex] - [tex]36 \pi x^2[/tex]
=> Final area of the Yard = [tex]2x^2(133 - 18 \pi)[/tex] (Option D)
6. Ans: Option (A) [tex]56x^2[/tex]
Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = [tex]60x^2[/tex]
Now the area of the stadium:
Area of the stadium = 1x * 4x = [tex]4x^2[/tex]
Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= [tex]60x^2[/tex] - [tex]4x^2[/tex]
=> Final area of the lot = [tex]56x^2[/tex] (Option A)
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Explanation:
Given: [tex]2x^4 - 8x^4[/tex]
Take the common out:
=> [tex]x^4(2 - 8)[/tex]
Hence: => [tex][tex]-6x^4[/tex][/tex] (Option B)
2. Ans: Option (D) [tex]-3y^5[/tex]
Explanation:
Given: [tex]6y^5 - 9y^5[/tex]
Take the common term(s) out:
=> [tex]y^5(6-9)[/tex]
Hence: => [tex]-3y^5[/tex] (Option D)
3. Ans: Option (B) [tex]9x^2 - 12x + 6[/tex] quadratic trinomial
Explanation:
Given: [tex]6 - 12x + 13x^2 - 4x^2[/tex]
The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.
=> [tex]13x^2 - 4x^2 - 12x + 6[/tex]
=> [tex]9x^2 - 12x + 6[/tex] (Option B)
4. Ans: Option (C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:
Common guppies: [tex]3.1x^2 +6.0x + 0.3[/tex]
Endler's guppies: [tex]4.2x^2 - 5.2x + 1.0 [/tex]
(add both)
-----------------------------------------------------------------
Total number: [tex]7.3x^2 +0.8x + 1.3[/tex]
-----------------------------------------------------------------
Hence the ans is Option(C) [tex]7.3x^2 + 0.8x + 1.3[/tex]
5. Ans: Option (D) [tex]2x^2(133 - 18 \pi )[/tex]
Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = [tex]266x^2[/tex]
Now the area of the circular fountain:
Area of the Circular Fountain = [tex] \pi r^2[/tex]
Since, r=6x
Therefore,
Area of the Circular Fountain = [tex] \pi (6x)^2 = 36 \pi x^2[/tex]
Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = [tex]266x^2[/tex] - [tex]36 \pi x^2[/tex]
=> Final area of the Yard = [tex]2x^2(133 - 18 \pi)[/tex] (Option D)
6. Ans: Option (A) [tex]56x^2[/tex]
Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = [tex]60x^2[/tex]
Now the area of the stadium:
Area of the stadium = 1x * 4x = [tex]4x^2[/tex]
Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= [tex]60x^2[/tex] - [tex]4x^2[/tex]
=> Final area of the lot = [tex]56x^2[/tex] (Option A)
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