A diver with a mass of 70.0 kg stands motionless at the top of a diving platform 3.0 m high. The diver’s initial vertical speed is zero. What is the diver’s potential energy relative to the water surface?

Respuesta :

The answer is 2,058J. 

You can solve for the potential energy using the formula:

[tex]PE=mgh[/tex]

Where:
PE= potential energy
m= mass
g= 9.8m/s² (This is constant. This is acceleration due to gravity because the diver is positioned above the surface of the Earth.)
h= height

The given in your problem are the following:
m = 70kg
h = 3.0 m
g = 9.8m/s² (Again this is constant)

Just plug in your given in the formula and solve:
[tex]PE=mgh[/tex]
           [tex]=(70kg)(9.8m/s^{2})(3.0m)[/tex]
           [tex]=2,058kg.m^{2}/s^{2} or 2,058J[/tex]