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How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret

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Answer is: 0,0105 moles of calcium chloride have delivered to the flask.
V(CaCl₂) = 20,53 mL ÷ 1000 mL/L = 0,02053 L.
c(CaCl₂) = 0,511 M = 0,511 mol/L.
n(CaCl₂) = c(CaCl₂) · V(CaCl₂).
n(CaCl₂) = 0,511 mol/L · 0,02053 L.
n(CaCl₂) = 0,0105 mol.
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We have that for the Question "How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret" it can be said that no of moles of solute is

[tex]no of moles of solute=0.011[/tex]

From the question we are told

How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret

Generally the equation for the morality  is mathematically given as

[tex]M=\frac{no of moles of solute}{volume of solution litre}[/tex]

Therefore

[tex]The volume of CaCl_2 =\frac{20.53}{1000}[/tex]

Hence

no of moles of solute=molality*volume*solution

[tex]no\ of\ moles\ of\ solute=0.511*\frac{20.53}{1000}[/tex]

[tex]no of moles of solute=0.011[/tex]

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